(3x-9)^(2)=2x+2(2x+2+27)

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Solution for (3x-9)^(2)=2x+2(2x+2+27) equation: 



(3x-9)^(2)=2x+2(2x+2+27)

We move all terms to the left:

(3x-9)^(2)-(2x+2(2x+2+27))=0

We add all the numbers together, and all the variables

(3x-9)^2-(2x+2(2x+29))=0



We calculate terms in parentheses: -(2x+2(2x+29)), so:

2x+2(2x+29)

We multiply parentheses

2x+4x+58

We add all the numbers together, and all the variables

6x+58

Back to the equation:

-(6x+58)



We get rid of parentheses

(3x-9)^2-6x-58=0

We add all the numbers together, and all the variables

-6x+(3x-9)^2-58=0

We move all terms containing x to the left, all other terms to the right

-6x+(3x-9)^2=58

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